9(1/(x+2))^2-10(1/(x+2))=-1

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Solution for 9(1/(x+2))^2-10(1/(x+2))=-1 equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

9*(1/(x+2))^2-(10*(1/(x+2))) = -1 // + 1

9*(1/(x+2))^2-(10*(1/(x+2)))+1 = 0

9*(1/(x+2))^2-10*(x+2)^-1+1 = 0

(9*1^2)/((x+2)^2)-10/(x+2)+1 = 0

(9*1^2)/((x+2)^2)+(-10*(x+2))/((x+2)^2)+(1*(x+2)^2)/((x+2)^2) = 0

1*(x+2)^2-10*(x+2)+9*1^2 = 0

x^2-10*x+4*x-11+4 = 0

x^2-6*x-7 = 0

x^2-6*x-7 = 0

x^2-6*x-7 = 0

DELTA = (-6)^2-(-7*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+6)/(1*2) or x = (6-64^(1/2))/(1*2)

x = 7 or x = -1

(x+1)*(x-7) = 0

((x+1)*(x-7))/((x+2)^2) = 0

((x+1)*(x-7))/((x+2)^2) = 0 // * (x+2)^2

(x+1)*(x-7) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-7 )

x-7 = 0 // + 7

x = 7

x in { -1, 7 }

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